Q:

You and your friend are selling raffle tickets for a new laptop. you sell 14 more then your friend sells. Together you and your friend sell 58 tickets. Write a system of linear equations that represent this situation. How many did each of you sell?

Accepted Solution

A:
Answer:[tex]y=x+14[/tex][tex]x+y=58[/tex]You sold 22 tickets and your friend sold 36 tickets.Step-by-step explanation:1. Let´s name the variables as the following:x = quantity of tickets sold by youy = quantity of tiquets sold by your friend2. As you sold 14 more than your friend, the first equation is:[tex]y=x+14[/tex] (Eq.1)3. As together sold 58 tickets, the second equation is:[tex]x+y=58[/tex] (Eq.2)4. Replacing the Eq. 1 in Eq. 2:[tex]x+x+14=58[/tex][tex]2x+14=58[/tex][tex]2x=58-14[/tex][tex]2x=44[/tex][tex]x=\frac{44}{2}[/tex][tex]x=22[/tex]Then you sold 22 tickets5. Replacing the value of x result in Eq.1:[tex]y=x+14[/tex][tex]y=22+14[/tex][tex]y=36[/tex]Therefore your friend sold 36 tickets.